permanent of square matrix

[Werner]

(01-09-2024 09:49 PM)John Keith Wrote:  The variable p is much larger than the final value, up to 3 digits larger for the sizes of matrices we are dealing with. This limits the size of the largest matrix we can use on the 71, 28 and 48 which are limited to 12-digit numbers. Valentin's program is not as fast, but it does not have this problem. Perhaps there exists a happy medium somewhere, but the math behind these algorithms is way above my head.

Just do v/2, use dj=+/-1 again and double the result. If all vi are odd, this will not help ;-)

Cheers, Werner