lambertw, all branches
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01-21-2024, 06:03 PM
Post: #25
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RE: lambertw, all branches
(01-21-2024 04:35 PM)Gil Wrote: And log1p(a)= (a*1) × EXP (a*1)? I don't follow where EXP comes from log1p(a) = ln(1+a), but evaluated more accurately when re(a) is tiny. Quote:My question is relative to the guess of xo, Sure. W0(z, |z|→∞) = ln(z) |
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