Perfect Parking
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03-27-2024, 01:11 AM
Post: #1
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Perfect Parking
From The Geometry of Perfect Parking:
Quote:How much extra length (above the length of your car) do you need to parallel park? The length of the parking space must be at least the length of my car plus \( \sqrt{(r^2 - \ell^2) + (\ell + k)^2 - \left( \sqrt{r^2 - \ell^2} -w \right)^2} - \ell - k \) where \(r\) is the radius of my car’s kerb-to-kerb turning circle, \(\ell\) is my car’s wheel-base (the distance between the centres of the front wheel and the corresponding back wheel), \(k\) is the distance from the centre of the front wheel to the front of the car, and \(w\) is the width of one of the parked cars: the one near the front of my car once I’ve parked. I came up with the following program for the HP-42S, which should work with most HP calculators: Code: 00 { 33-Byte Prgm } Example \( \begin{align} r &= 5.4\text{m} \\ \ell &= 2.6\text{m} \\ k &= 1.3\text{m} \\ w &= 1.7\text{m} \\ \end{align} \) 5.4 ENTER 2.6 ENTER 1.3 ENTER 1.7 XEQ "PARKING" 1.4303 Can you do better? This is the same program for the HP-15C: Code: 001 { 34 } X<=>Y |
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Messages In This Thread |
Perfect Parking - Thomas Klemm - 03-27-2024 01:11 AM
RE: Perfect Parking - SlideRule - 03-27-2024, 04:36 PM
RE: Perfect Parking - 0db - 04-14-2024, 06:11 PM
RE: Perfect Parking - Werner - 04-15-2024, 06:19 AM
RE: Perfect Parking - Thomas Klemm - 04-15-2024, 06:22 AM
RE: Perfect Parking - toml_12953 - 04-16-2024, 11:04 AM
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