Mathematician Finds Easier Way to Solve Quadratic Equations

[Albert Chan]

(04-27-2024 08:21 PM)Rolief_Rechner Wrote:  The formula is derived by completing the square.
It was checked with Wolfram Alpha, attached.

This is where it get wrong. (x + y)^2 = x^2 + 2 xy + y^2

a*x^2 + b*x + c = 0
x^2 + (b/a)*x + (c/a) = 0
x^2 + (b/a)*x + (b/(2a))^2 = (b/(2a))^2 - (c/a)
(x + b/(2a))^2 = (b/(2a))^2 - (c/a)

x = -b/(2a) ± √((b/(2a))^2 - (c/a))