Dice probabilities
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04-29-2024, 09:22 PM
Post: #7
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RE: Dice probabilities
Dice = (x^2 + x^1 + x^0) / 3 = 100% // see Probability-generating function
Dice^5 = 100% probability too. From this distribution, just pick what we needed. >10101^5 // (x^2+x+1)^5, for x=100 1.05153045515E20 >(1+5+15+30+45+51+45+30+15+5+1)/3^5 1 >(1+5+15+30)/3^5 // P(sum >= 7) .20987654321 |
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