HP 12C Fibonacci Sequence

[Werner]

(08-08-2024 07:40 PM)C.Ret Wrote:  To do this, properly initialize your HP-12C:
(f) [CLEAR FIN ]
[ 5 ] (g)[ √x ] [CHS] [1/x] [ PV ] initializes the constant factor of the Binet Formula in the Present value register PV.
[ 5 ] (g)[ √x ] [ 1 ] [ - ] [ 5 ][ 0 ][ × ][ i ] initializes the under-exponential part of the same formula in the Interest register i%.

Gives wrong results as of n=40
For a few more correct results, define the constants more accurately as
.2 (g) [√x] [CHS] [PV] and
200 [ENTER] 5 [√x] 1 [+] [/] [i]
Now the first wrong result is for n=44. Mh. Doesn't gain a lot..

Cheers, Werner