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Gamma function
08-16-2024, 06:06 PM (This post was last modified: 08-16-2024 06:59 PM by ftneek.)
Post: #6
RE: Gamma function
Nice, simple solution.

It works here:
(((-s)*Gamma((2/3),∞)+s*Gamma((2/3),0))/(s*s^(2/3)))(('Gamma') = Gamma2)
-> s*Gamma((2/3))/((s^(1/3))^2*s)

But not here:
(laplace(t^(-1/3),t,s))(('Gamma') = Gamma2)
-> Bad argument value

I also prefer not to type Gamma=Gamma2 everytime:
Code:
g3:=(ex)->BEGIN  
  ex(('Gamma') = Gamma2);  
END;

Is there an easy way to make the laplace example work using this method?

- neek
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Messages In This Thread
Gamma function - robmio - 08-06-2020, 01:56 PM
RE: Gamma function - robmio - 08-06-2020, 03:49 PM
RE: Gamma function - robmio - 08-06-2020, 06:14 PM
RE: Gamma function - ftneek - 08-16-2024, 09:36 AM
RE: Gamma function - Albert Chan - 08-16-2024, 11:47 AM
RE: Gamma function - ftneek - 08-16-2024 06:06 PM
RE: Gamma function - Albert Chan - 08-16-2024, 08:04 PM
RE: Gamma function - ftneek - 08-16-2024, 08:42 PM
RE: Gamma function - Albert Chan - 08-16-2024, 11:46 PM



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