Quiz: calculating a definite integral

[walter b]

(01-03-2014 05:18 AM)Thomas Klemm Wrote:  

(01-02-2014 11:39 PM)Bunuel66 Wrote:  iterating: \(\int_{0}^{1}x^n\log(x)^n dx=\frac{(-1)^n n!}{n^n}\)

This should be: \(\int_{0}^{1}x^n\log(x)^n dx=\frac{(-1)^n n!}{(n+1)^{n+1}}\)

Then you won't run into problems with \(0^0\).

'This should be' ?? Christmas is over. Both formulas don't mean the same, there can be only one correct.

d:-?