Integrals in solve app?

[Han]

In regular math type, you are asking the solver to solve:

\[ \int_0^B (8A-27A^3)\ dA = 0.3 \]

or equivalently

\[ 4B^2-\frac{27}{4}B^4 = 0.3 \]

… but you're asking the calculator to solve for A.

Quote:I'm getting bad guess messages...tried integral symbol, and also int(8*A-27*A^3,A,0,B)=3
Used guesses for B of .3 and solved for A in the solve app.

A is not even a variable in this equation. It appears in the integral, but it is a dummy variable, no? I do think there may be a bug of sorts since A is not truly a variable. So you should really only be allowed to solve for B. When A is set to its default value (of zero), you will generate an error because the calculator thinks you're integrating with respect to the "variable" 0 -- which of course makes no sense.