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Question about CAS and Graphing
11-24-2014, 02:12 PM
Post: #27
RE: Question about CAS and Graphing
(11-24-2014 06:33 AM)Angus Wrote:  "This is unnecessary. In CAS, simply type:
F1:=f('X');
which evaluates f at the symbolic value 'X' and properly provides a formula for F1."


Does that work for you guys?
Type F1:=f('X') as advised. But when switching to function app I see a Syntax Error displayed for F1(X).
Checking the function gives 'x(X)^2'/2...

Trying Function.F2:=f('X'). Again there is a syntax error for F2(X) in the function app and the formula displayed when tapping that error id 'x(0)^2'/2.

Can someone point out what is wrong?

Did you previously define f as a function (example: f(x):=1/2*x^2) or did you merely define f as an expression (example: f:=1/2*x^2)?

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Messages In This Thread
RE: Question about CAS and Graphing - Han - 09-24-2014, 10:14 PM
RE: Question about CAS and Graphing - Han - 09-25-2014, 01:35 PM
RE: Question about CAS and Graphing - jte - 11-22-2014, 03:01 AM
RE: Question about CAS and Graphing - Han - 11-22-2014, 02:31 PM
RE: Question about CAS and Graphing - jte - 11-23-2014, 06:31 PM
RE: Question about CAS and Graphing - Han - 11-23-2014, 08:42 PM
RE: Question about CAS and Graphing - jte - 11-26-2014, 06:02 AM
RE: Question about CAS and Graphing - Han - 11-22-2014, 02:16 PM
RE: Question about CAS and Graphing - Han - 11-22-2014, 07:26 PM
RE: Question about CAS and Graphing - Han - 11-23-2014, 08:41 PM
RE: Question about CAS and Graphing - Han - 11-24-2014, 11:47 AM
RE: Question about CAS and Graphing - Han - 11-24-2014, 01:29 PM
RE: Question about CAS and Graphing - Han - 11-24-2014 02:12 PM



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