Problem solving for a variable in Prime
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12-28-2014, 10:48 PM
(This post was last modified: 12-29-2014 12:39 AM by Snorre.)
Post: #8
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RE: Problem solving for a variable in Prime
Hello compsystems,
Your expression Quote:solve( ∫( (1/(√(2*π)*s))*e^(-(t-u)^2/(2*s^2)),t, t,∞), t=0.1 )looks odd because you're using the same name "t" for two different variables. You should rename one of them (either the red or blue), e.g. to τ (tau). (1) t within the integrand refers to the integration variable t. (2) t to be solved refers to the integration lower limit t. (3) t and t are two distinct variables (each having their own context/scope/lifetime). So you are trying to find a lower integration limit t (somewhere near 0.1) so that the integral becomes zero (the to-solve-equation is implicitly set to =0), which would only hold if both limits are equal (since your integrand has everywhere the same sign). But your expression differs from that of factor. Look at his screenshots: Quote:solve( ∫( (1/(√(2*π)*s))*e^(-(t-u)^2/(2*s^2))=0.1, t, t, ∞), s )Here we have two distinct t again. Now we're searching for s so that the integral becomes 0.1. Since the lower limit t is a free variable the result depends on whatever t is set to. Hello factor, I do not know the original problem, but I think the lower limit should not be t but something like either 0 or -∞. (On your calc you seem to have set t to 40, which becomes the lower integration limit). Maybe you're not searching for an s but for t as compsystems suggested (if so, don't name your integration variable also t since it's not forbidden but a bit confusing). Furthermore I doubt the Prime is able to solve that integral. You should paraphrase it in terms of "erf"/"erfc"/"NORMALD_CDF"/"NORMALD_ICDF" functions and set your lower integration limit and u to concrete values before solving numerically. |
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Messages In This Thread |
Problem solving for a variable in Prime - factor - 12-28-2014, 06:09 AM
RE: Problem solving for a variable in Prime - akmon - 12-28-2014, 10:42 AM
RE: Problem solving for a variable in Prime - factor - 12-28-2014, 10:47 AM
RE: Problem solving for a variable in Prime - akmon - 12-28-2014, 10:53 AM
RE: Problem solving for a variable in Prime - factor - 12-28-2014, 11:04 AM
RE: Problem solving for a variable in Prime - Helge Gabert - 12-28-2014, 07:12 PM
RE: Problem solving for a variable in Prime - Snorre - 12-28-2014 10:48 PM
RE: Problem solving for a variable in Prime - factor - 12-29-2014, 01:54 PM
RE: Problem solving for a variable in Prime - Snorre - 12-29-2014, 03:34 PM
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