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Residues
02-07-2015, 06:39 PM (This post was last modified: 02-07-2015 11:20 PM by salvomic.)
Post: #1
Residues
hi all,
calculating residue of \( sin(z)^{-1} \) in z=0 I get 1, ok.
Calculating residue of \( sin(z^{-1}) \) in z=0 I get 0, but I think I should get 1, instead...
(The Laurent series is 1/z-1/(6 z^3)+1/(120 z^5)-1/(5040 z^7)+1/(362880 z^9)-1/(39916800 z^11)+o((1/z)^13) ...)
Am I wrong?

Thank you
Salvo

EDIT: here (and in a book of mine) they say 1...

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Messages In This Thread
Residues - salvomic - 02-07-2015 06:39 PM
RE: Residues - parisse - 02-08-2015, 07:13 AM
RE: Residues - salvomic - 02-08-2015, 08:57 AM
RE: Residues - parisse - 02-08-2015, 02:53 PM
RE: Residues - salvomic - 02-08-2015, 03:34 PM
RE: Residues - parisse - 02-09-2015, 08:01 AM



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