HP Prime lockup (not a complaint)
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03-22-2015, 12:36 AM
Post: #6
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RE: HP Prime lockup (not a complaint)
hi
I have similar experience in CAS with an other computation: I am trying to calculate and simplify a trivial differentiation in the complex space ∂(√(z-i))/∂z , where z ∈ C The answer should be: 1/(2√(z-i)) Trying different ways in the PRIME: In CAS mode entering: diff(√(z-i),z) results in some wacko answer: 1/2*(()*diff(im(z),z)/(re(z)+√((re(z))^2+(im(z)-1)^2))+()*(-(diff(re(z),z))-1/2*(2*diff(re(z),z)*re(z)+2*diff(im(z),z)*(im(z)-1))/√((re(z))^2+(im(z)-1)^2))*(im(z)-1)/(re(z)+√((re(z))^2+(im(z)-1)^2))^2)*√(2*(re(z)+√((re(z))^2+(im(z)-1)^2)))+1/2*(diff(re(z),z)+1/2*(2*diff(re(z),z)*re(z)+2*diff(im(z),z)*(im(z)-1))/√((re(z))^2+(im(z)-1)^2))*(()*(im(z)-1)/(re(z)+√((re(z))^2+(im(z)-1)^2))+1)/√(2*(re(z)+√((re(z))^2+(im(z)-1)^2))) simplify(diff(√(z-i),z)) results in a dump followed by lock up which I have to reboot to recover from. What am I doing wrong here? Interestingly the prime have not problem calculating: diff(√(z-1),z) where z ∈ R (I assume Prime assumes R) which results in the correct: (1/2)/√(z-1) My Prime has the following configuration: Model: NW280AA Software: 6975 Hardware: A CAS: 1.1.2-11 OS: SDKV0.44_R.521 CAS settings are: Complex: ticked Use i: ticked |
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