Ans and ^ (1/3)

[BartDB]

(03-30-2015 08:36 PM)Helge Gabert Wrote:  

(03-30-2015 06:08 PM)parisse Wrote:  Operator precedence : -a^b is -(a^b) not (-a)^b

No, I'm sorry if I wasn't clear enough

Ans^(1/3) returns a different root than (-1.2)^(1/3). That's all.

Mr Parisse gave the correct answer:

When you type -1.2^(1/3) operator precedence evaluates the power before the negative (on old calculators, a negative from +/- key was seen as part of the number, but some far eastern country* decided to treat it as 0-1.2^(1/3) and now all are following suit).

However, Ans is a variable containing the last calculated result. Thus Ans^(1/3) is the same as e.g. B^(1/3) where -1/2 is stored in B. Therefore it is evaluated as (-1/2)^(1/3) because the value of the variable as a whole is -1/2.

EDIT: in your first post you were comparing Ans^(1/3) vs -1/2^(1/3). In your reply to Mr. Parisse you are comparing Ans^(1/3) vs (-1/2)^(1/3) ... this second case should give the same answer because of the bracket around -1/2.

Best regards.

*my personal observation: i first noticed this on Casio's