desolve y'=(x+y)^2
|
05-02-2015, 05:30 AM
Post: #13
|
|||
|
|||
RE: desolve y'=(x+y)^2
Xcas can solve this equation. It is a Ricatti equation, you can solve it by giving a particular solution, otherwise the system rewrites it as a 2nd order equation.
|
|||
« Next Oldest | Next Newest »
|
User(s) browsing this thread: 3 Guest(s)