About LU factorization

[salvomic]

(06-04-2015 11:30 AM)DrD Wrote:  For your matrix M1:=!([[2,1,1],[4,−6,0],[−2,7,2]], I get:

L1:=LU(M1) = {[[1,0,0],[0.5,1,0],[−0.5,1,1]],[[4,−6,0],[0,4,1],[0,0,1]],[[0,1,0],[1,0,0],[0,0,1]]}

Since L1(1)=[[1,0,0],[0.5,1,0],[−0.5,1,1]] (Lower triangular, has one's in diagonal) it would be the Doolittle method.

By the way, I went through Gil Strang's MIT online classes. I really enjoyed them!

Gil Strang books are also amazing, not only good to learn, yes.

Maybe you've transcript different numbers for matrix or LU, or we are using different LU() or...
I get {[1,3,2], [[1,0,0], [-1,1,0], [2,-1,1]], [[2,1,1], [0,8,3], [0,0,1]]}, I'm curious...

Salvo