HP 48GX Division by Zero
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06-06-2015, 11:56 PM
(This post was last modified: 06-07-2015 01:20 AM by Dave Britten.)
Post: #6
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RE: HP 48GX Division by Zero
What about arcsin((n2-n1)/SQRT((e2-e1)^2+(n2-n1)^2))?
EDIT: That just covers 1st quadrant, though. You'd have to figure out signs to get the correct angle. Or better yet, just make the 48 do the work for you. Code: \<< SWAP - ROT ROT SWAP - SWAP R\->C ARG \>> Input: 4: E1 3: E2 2: N1 1: N2 Output: 1: Azimuth |
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Messages In This Thread |
HP 48GX Division by Zero - MNH - 06-03-2015, 11:55 PM
RE: HP 48GX Division by Zero - Bruno - 06-05-2015, 09:03 AM
RE: HP 48GX Division by Zero - Raymond Del Tondo - 06-05-2015, 09:47 AM
RE: HP 48GX Division by Zero - Bruno - 06-05-2015, 10:05 AM
RE: HP 48GX Division by Zero - MNH - 06-06-2015, 08:10 PM
RE: HP 48GX Division by Zero - Dave Britten - 06-06-2015 11:56 PM
RE: HP 48GX Division by Zero - MNH - 06-07-2015, 03:32 AM
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