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[Gerson W. Barbosa]

(07-12-2015 11:08 AM)Thomas Klemm Wrote:  

(07-11-2015 05:30 PM)Gerson W. Barbosa Wrote:  \[\frac{3}{2}\cdot \pi ^{18}+\frac{6!-5!+\frac{\pi ^{-\pi }}{9}}{7}\cdot \pi ^{4}\]

I'm always amazed by your pandigital expressions. Do you use a program to find them?

Hi, Thomas!

No program, only a WP 34S set to double precision and about one hour's time. The pandigital form was almost an accident. At a certain point I noticed I had an expression with only 5 and 9 missing, but with two zeros, so I thought it would not be too difficult to go pandigital:


\[\frac{3\pi ^{18}}{2}+\frac{600\pi ^{4}}{7}+e^{-\pi }\]

These will give results in excess of three on HP 10-digit calculators, like the HP-15C. Although inaccurate, the following expression will give the expected result on the Voyagers:

\[\frac{3\pi ^{3(3 + 3)}}{3-\frac{3}{3}}+\frac{3^{3}\pi ^{3+\frac{3!}{3}}}{.33\times 3}\]

No program has been needed to find this one either :-)

Cheers,

Gerson.