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HP50g or other: U. of Houston calc exams
08-12-2015, 10:53 PM
Post: #27
RE: HP50g or other: U. of Houston calc exams
(08-12-2015 09:29 PM)Gilles Wrote:  then S=1/2.||AB /\ AC ||

Which of course is the same since:

\(
\begin{align}
(B-A)\wedge (C-A)&=B\wedge C-B\wedge A-A\wedge C+A\wedge A \\
&=B\wedge C+A\wedge B+C\wedge A+0 \\
&=A\wedge B+B\wedge C+C\wedge A \\
\end{align}
\)

Cheers
Thomas
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RE: HP50g or other: U. of Houston calc exams - Thomas Klemm - 08-12-2015 10:53 PM



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