Simple parallel circuit problem

[Gerson W. Barbosa]

(08-25-2015 02:21 AM)Steve Simpkin Wrote:  That was fun! Well not as much fun as typing "58008" on an LED calculator and reading it upside down, but fun neverless

Starting with 163*π ~ 512, I came up with

\[\frac{163+2^{20}}{163\times 2^{11}}\]

The rational approximation is interesting perhaps, as it involves two instances of the last Heegner number and two powers of two, but it is only good to eight places. So I thought the parallel circuit would be a little more interesting :-)