Year(s) Month(s) Day(s) between 2 dates

[Dieter]

(10-23-2015 04:38 PM)ggauny@live.fr Wrote:  Personaly I prefer 48 years 6 months AND 10 days, because "5+5=13" hurt me.

Whether the first value is 5 (days in February) or 8 (days in August) is something that can be discussed. ;-)

But if it really hurts so much you can adjust the program without major effort. Currently the number of days is calculated as the difference between 23 Aug 1999 and 5 Sep 1999, which is 13 days, obtained via the ΔDAYS function. If you prefer the other approach, all you need is the difference between 23 Feb 1951 and 5 Mar 1951, which is 10 days. In my original program this is the part between line 12 and 24.

Dieter