newRPL: Handling of units

[emece67]

Hi all,

In a case like: what's the final temperature of 2 kg of liquid water at 20ºC that is heated if the total amount of heat transferred to it is 25000 J?

From \(Q = mC\Delta T\) you will get \(\Delta T = {Q\over mC}\), with \(C=4182 {J\over kg \Delta K}\) being the specific heat of water at 20ºC. With this you get \[\Delta T = {25000 J\over 2kg · 4182 {J\over kg \Delta K}} = 2.989 \Delta K\]

Then the final temperature will be: \(T_0+\Delta T = 20 ºC + 2.989 \Delta K =\) Inconsistent units.

I don't see the point on \(T\) and \(\Delta T\) units being inconsistent in addition and subtraction.

EDIT: and for the \({T\over\Delta T}\) and \({\Delta T\over T}\) cases. Will: convert \(T\) to the absolute scale associated with \(\Delta T\); discard units; perform division, solve the \({K\over\Delta K}\) glitch? This way 10ºF / 1ΔK = 469.67ºR / 1ΔºC = -12.22ºC / 1ΔK = 260.928 K / 1ΔºC = 260.928.