can the prime really not solve this integral?

[Tugdual]

(02-27-2014 02:11 PM)Terje Vallestad Wrote:  Possibly a dumb question, but why is the result dependent on the Rad/Deg setting when solving this? If the calc is in Degrees the result (on my calculator) is 372.07.... Other integrals involving exp(x) (for instance int(exp(x^2),x,0,.5)) seems not to be influenced by the Deg/Rad setting. Am I missing something?
Cheers, Terje

Had the same question... so I took my 15C and tried both. As a result I always get pi^4/15 deg or rad which makes much more sense.