Testing the mathjax engine

[Csaba Tizedes]

(05-08-2016 08:56 PM)emece67 Wrote:  From \(Q = mC\Delta T\) you will get \(\Delta T = {Q\over mC}\), with \(C=4182 {J\over kg \Delta K}\) being the specific heat of water at 20ºC. With this you get \[\Delta T = {25000 J\over 2kg · 4182 {J\over kg \Delta K}} = 2.989 \Delta K\]

Then the final temperature will be: \(T_0+\Delta T = 20 ºC + 2.989 \Delta K =\) Inconsistent units.

\(\frac{N_i}{D_i}=\frac{N_{i-1}}{D_{i-1}}+\frac{1}{F_i}=\frac{F_i · N_{i-1}+D_{i-1}}{D_{i-1} · F_i}\)

JÍHÁÁÁÁ!