(12C) Numeric Solver

[Dwight Sturrock]

(04-14-2017 04:33 PM)Dieter Wrote:  

(04-13-2017 01:50 AM)Dwight Sturrock Wrote:  This solver uses Newton's method to solve f(x)=0. It is an adaptation of the HP-25 solver (HP-25 Application Programs, Chapter 5).

The program calculates h (in R3) as x/1E5. This does not work for x=0 since it yields h=0 and so the derivative gets zero, leading to a division by zero.

But this can be fixed easily:

...
RCL 1
RCL 1
X=0?
e^x
EEX
4
/
STO 3
...

After this change the GTOs of course need to be updated.

One more tip: instead of 2 [Y^X] always use [ENTER] [x]. This is much faster and exact.

Dieter

Thanks Dieter, I'll try your enhancements and repost.