Programming Exercise (HP-15C, 15C LE - and others)

[Gerson W. Barbosa]

(03-26-2014 02:22 AM)churichuro Wrote:  

(03-26-2014 12:00 AM)Gerson W. Barbosa Wrote:  Would you try Thomas Klemm's idea, that is, evaluating two terms per loop? Thanks!

Code:


suma=0
for n= 5000 to 1 step -1
  suma= suma + 1 / (n - 1) - 1 / n
next
fix 10.9
print
print "Sum ="; suma
end

Do this change: for no get error "Divide by zero" (well, this error but in spanish)
for n=5000 to 2 step -1

get suma= 0.999800000 in about 3 sec

if change to
for n=10000 to 2 step -1
get suma= 0.999900000 in 5.5 sec

Oops! this should have been
...
for n=10000 to 2 step -2
...

Sorry!