antilog on 12C

[Dieter]

(08-17-2017 09:18 AM)Zac Bruce Wrote:  Evening all,

It's lunch break over here. ;-)

(08-17-2017 09:18 AM)Zac Bruce Wrote:  I'm hoping someone more mathematically minded than me can tell me how I can calculate the common antilog on a HP 12c, if it is indeed possible.

The common antilog is 10^x. So simply type 10 [x<>y] [y^x].

Or if you prefer a somewhat more complicated method: 10 [ln] [x] [e^x].
The latter may cause slight roundoff errors, e.g. x=5 returns 100 000,0005 instead of exactly 100 000.

(08-17-2017 09:18 AM)Zac Bruce Wrote:  I know that the common logarithm can be calculated by e.g. 'x'LN 10LN /
but my feeble powers of math doesn't let me see the solution using the natural antilog in a similar way, if this is possible.

The natural antilog is e^x. The 12C has a key for that. ;-)

Dieter