[CAS] Integrals

[DrD]

Thanks for the explanation, but it doesn't quite fit the problem. In this case, and as Wolfram correctly interprets, it's treated as a proper integral. The integrals in my examples, do not converge; there are no solutions, per the original formula.

Over the boundary indicated in the integrals, -1 to +1, zero is not excluded. Since the denominator vanishes, at x=0, they do not converge. They asymptote at the singularity prevents it. I don't think infinity is a correct solution.

I haven't tried this in other CAS software, but now my curiosity is tweaked, so I think I will. My granddaughter is in a calc 1 class and encountered this particular kind of problem. The correct answer, according to her teacher, was that it does not have a solution. In the next class, calc 2, they cover improper integrals, and at that time I'm pretty sure they will cover similar problems using the technique you describe.

-Dale-