Integrate question

[webmasterpdx]

I got the same as you did, and I'm thinking the following. When integrating without limits in Xcas/Cas, it just gives you an algebraic result and you are to assume the + constant part yourself.
This means that if the result contains a constant term, it's still correct (it just reduces the constant term by that much...it's still a constant).
e.g. integrate(x^2,x) is 1/3 x^3 + constant, so if it gave you a result of 1/3 x^3 + 1 is just as valid as just 1/3 x^3. i.e. You can ignore the constant terms and replace by "+ constant".

I'm also curious though where it's getting the -1/48 from...
-Donald