HP 15C and INT(1/√(1-x),0,1)

[peacecalc]

Hello Salvo,

try your little program LBL1 without step 03 and 05 (both ENTER).

Because if you use your function with lets say 0.2 you get:

at step 01: -0.2 x-reg
at step 02: -0.2 x-reg, y-reg
at step 04: 0.8 x-reg, -0.2 yreg
at step 05: 0.8 x-reg, 0.8 yreg, -0.2 z-reg
at step 07: 1/√0.8 x-reg, 0.8 yreg, -0.2 z-reg

but the values in y-reg and z-reg are useless for the build-in integral-program, it may interfer with next looping because then t-reg is loaded and this reg copies it's value to the z-reg if there is a stack-down command.

Okay, Dieter was fast as flash, but I can't delete my post.