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(12C) ~Γ(x+1)
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12-11-2017, 01:58 PM
Post: #3
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RE: (12C) ~Γ(x+1)
(12-11-2017 02:19 AM)Gerson W. Barbosa Wrote: This is based on formula 27 here, slightly modified to improve accuracy. Maybe you should change the final steps where xx is divided by ex. Since both terms are calculated separately especially the first one may cause an overflow much earlier than neccessary. What about (x/e)x? Or maybe you have an even better idea?! Dieter |
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(12C) ~Γ(x+1) - Gerson W. Barbosa - 12-11-2017, 01:27 AM
RE: (12C) ~Γ(x+1) - Gerson W. Barbosa - 12-11-2017, 02:19 AM
RE: (12C) ~Γ(x+1) - Dieter - 12-11-2017 01:58 PM
RE: (12C) ~Γ(x+1) - Gerson W. Barbosa - 12-11-2017, 02:15 PM
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