Newton's method
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01-01-2018, 03:49 PM
Post: #2
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RE: Newton's method
Hi Namir, I like the compactness of the solution! I hope you don't mind a few tweaks that perhaps make it better:
Code:
With these changes, if you have functions in the Function App that plot nicely like for example F1(X)=17*SIN(1.26*X-90)-5, then you can run NEWTON("F1(X)",1,0.00000001) and find the root 1.85233166719. |
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Newton's method - Namir - 12-27-2017, 03:41 AM
RE: Newton's method - Mark Power - 01-01-2018 03:49 PM
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