Partial factorization?

[DrD]

No. That's much too cumbersome! The idea is a simple root solution, so I need this particular factorization, in that particular example, so:

\[\sqrt{16 {{x}^{8}}+8 {{x}^{4}}+1} = \sqrt{(4 {{x}^{4}}+1)^{2}} = {4*{x}^{4}+1}\]

I hope the latex works! (Square root of the expression squared is the idea).

-Dale-