Kepler's 2nd. Law
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02-13-2018, 08:06 AM
(This post was last modified: 02-13-2018 08:07 AM by Ángel Martin.)
Post: #4
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RE: Kepler's 2nd. Law
(02-13-2018 01:07 AM)toml_12953 Wrote:(02-12-2018 09:53 AM)Ángel Martin Wrote: Example: calculate the area swept between a1 = pi/4 and a2 = 3.pi/4, if the ellipse parameters are a= 2, b= 3 Mmm... something's fishy. I consistently get 1.989554087 using a1 = pi/4 (45 degrees) and a2 = 3.pi/4 (135 degrees). Besides, it's not possible to get the same as the web applet - which uses centered sectors, not focus-centered ones. In fact, using the angles above the applet shows an Area result of 3.5280156212854 Could you double check? "To live or die by your own sword one must first learn to wield it aptly." |
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