OEIS A229580 mini challenge (RPL)
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05-02-2018, 12:14 PM
Post: #24
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RE: OEIS A229580 mini challenge (RPL)
(05-02-2018 05:16 AM)Gerald H Wrote: My offering: Thank you, Gerald, but I think there is no problem if you inform them yourself. After all, in order do solve this little problem you’ve managed to derive a formula as well (as have others). I would suggest the formula valid for n > 1, that is, without the ceiling part. I arrived at that OEIS sequence when testing a continued fraction with consecutive denominators 3, 20 and 112. Since a continued fraction is evaluated backwards, a recursive formula wouldn’t help. Gerson. |
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