HP Forums / HP Calculators (and very old HP Computers) / General Forum v / OEIS A229580 mini challenge (RPL)

Post Reply 
OEIS A229580 mini challenge (RPL)
05-02-2018, 02:59 PM
Post: #25
Valentin Albillo Offline
Senior Member
 		Posts: 1,100
Joined: Feb 2015
RE: OEIS A229580 mini challenge (RPL)
(05-02-2018 12:14 PM)Gerson W. Barbosa Wrote:  I arrived at that OEIS sequence when testing a continued fraction with consecutive denominators 3, 20 and 112. Since a continued fraction is evaluated backwards, a recursive formula wouldn’t help.

Would you please elaborate on this ? What's the particular, complete continued fraction ? What makes you think a recursive formula wouldn't help ?

Regards.
V.
.
  
All My Articles & other Materials here:  Valentin Albillo's HP Collection
 
Visit this user's website Find all posts by this user
Quote this message in a reply
Post Reply 


Messages In This Thread
RE: OEIS A229580 mini challenge (RPL) - Valentin Albillo - 05-02-2018 02:59 PM



User(s) browsing this thread: 4 Guest(s)

Contact Us | The Museum of HP Calculators | Return to Top | Return to Content | Lite (Archive) Mode | RSS Syndication