Series test for convergence/divergence
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05-09-2018, 12:33 PM
Post: #2
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RE: Series test for convergence/divergence
Run series((2*n^2 + n) / √(4*n^7 + 3),n=inf) and look at the series expansion main term, here it's equivalent to n^(-3/2) (const sign) hence convergent.
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Messages In This Thread |
Series test for convergence/divergence - DrD - 05-09-2018, 11:15 AM
RE: Series test for convergence/divergence - parisse - 05-09-2018 12:33 PM
RE: Series test for convergence/divergence - DrD - 05-10-2018, 08:25 AM
RE: Series test for convergence/divergence - parisse - 05-10-2018, 01:31 PM
RE: Series test for convergence/divergence - DrD - 05-10-2018, 02:09 PM
RE: Series test for convergence/divergence - parisse - 05-11-2018, 03:30 PM
RE: Series test for convergence/divergence - DrD - 05-11-2018, 04:17 PM
RE: Series test for convergence/divergence - Benjer - 05-11-2018, 04:25 PM
RE: Series test for convergence/divergence - toshk - 05-11-2018, 06:28 PM
RE: Series test for convergence/divergence - parisse - 05-11-2018, 06:56 PM
RE: Series test for convergence/divergence - Benjer - 05-11-2018, 11:17 PM
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