∫−sin(x)*(cos(x))^7dx wrong answer? [SOLVED]
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05-26-2018, 05:58 AM
Post: #5
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RE: ∫−sin(x)*(cos(x))^7dx wrong answer?
Run ∫−(cos(x))^7*sin(x) (product argument reversed).
The integration algorithm tries to detect a f'(u)*u' form, the first one detected that works is used. Here you could use u=cos(x) or u=sin(x), both work (once you rewrite cos(x)^6 as (1-sin(x)^2)^3). Reverting the arguments will select the other possible u. |
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Messages In This Thread |
∫−sin(x)*(cos(x))^7dx wrong answer? [SOLVED] - vvolkan - 05-25-2018, 07:34 PM
RE: ∫−sin(x)*(cos(x))^7dx wrong answer? - Arno K - 05-25-2018, 09:52 PM
RE: ∫−sin(x)*(cos(x))^7dx wrong answer? - vvolkan - 05-25-2018, 10:09 PM
RE: ∫−sin(x)*(cos(x))^7dx wrong answer? - Aries - 05-26-2018, 07:24 AM
RE: ∫−sin(x)*(cos(x))^7dx wrong answer? - Arno K - 05-26-2018, 05:40 AM
RE: ∫−sin(x)*(cos(x))^7dx wrong answer? - parisse - 05-26-2018 05:58 AM
RE: ∫−sin(x)*(cos(x))^7dx wrong answer? - Arno K - 05-26-2018, 07:29 AM
RE: ∫−sin(x)*(cos(x))^7dx wrong answer? - Aries - 05-26-2018, 08:19 AM
RE: ∫−sin(x)*(cos(x))^7dx wrong answer? - parisse - 05-26-2018, 01:40 PM
RE: ∫−sin(x)*(cos(x))^7dx wrong answer? - vvolkan - 05-27-2018, 12:10 PM
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