[BUG ?] Who can explain to me the CAS options "Use i" and "complex"?

[dg1969]

Hi,

Here is an equation for which czeros returns a bad solution when none of the "use i" or "complex" options are checked... (Physical prime Firmware 13441).

\((3+2i)z+(1-i)\bar{z}=1\)

Code:

cZeros((3+2*i)*z+(1-i)*CONJ(z)=1,z)

give me the wrong answer \(\frac{1}{4+i}\)

But with "Use i" or with "Complex" checked it give the correct answer:

\(\frac{2-i}{11}\)

Code:

csolve((3+2*i)*z+(1-i)*CONJ(z)-1=0,z)

always return the good answer with or without options checked...

Thank's