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(Free42) roundoff for complex SQRT
02-12-2021, 02:45 PM
Post: #21
RE: (Free42) roundoff for complex SQRT
Resurrecting this old thread ...
When X = 0+iB, SQRT(X) should have equal real and imaginary parts (apart from the sign).
But that is (still) not the case.
The 48G algorithm I posted gives the correct result - in the 48, with its 3 extra digits, but not in Free42.
Example:

-1E-12
SQRT
SQRT
COMPLEX
-

equals -1E-37, exactly what you get when you follow the 48G algorithm.

Cheers, Werner
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RE: (Free42) roundoff for complex SQRT - Werner - 02-12-2021 02:45 PM



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