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Differential Equation Entry?
04-10-2018, 11:14 AM
Post: #1
Differential Equation Entry?
How can this be solved using the prime: (Ideally, returning BOTH a general and a particular solution.)

(y*e^x) dx + (y^2 - 1) dy = 0, AND y(0) = 1

Desired results:
y^2 - ln(y^2) = -2*e^x + c1; {General Solution}
y^2 - ln(y^2) = -2*e^x + 3; {Particular solution}
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Messages In This Thread
Differential Equation Entry? - DrD - 04-10-2018 11:14 AM
RE: Differential Equation Entry? - parisse - 04-10-2018, 11:53 AM
RE: Differential Equation Entry? - DrD - 04-10-2018, 01:22 PM



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