How to evaluate A Taylor series at a specific value

[ijabbott]

(08-24-2018 06:21 AM)parisse Wrote:  This is wrong: x:=1 followed by sin(x)|x=2 returns sin(2), and that's not easy to evaluate, you must have a "local" value of x (2) that takes precedence over the global value of x (1).

It would be nice if you could use the "where" operator "|" to temporarily undefine variables. For example: x:=1 followed by sin(x)|x=? (I'm not sure what the syntax ought to be here, but basically mark x as undefined) would return sin(x), ignoring the value assigned to x.