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∫−sin(x)*(cos(x))^7dx wrong answer? [SOLVED]
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∫−sin(x)*(cos(x))^7dx wrong answer? [SOLVED]
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∫−sin(x)*(cos(x))^7dx wrong answer? [SOLVED]
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05-25-2018, 09:52 PM
(This post was last modified: 05-25-2018 09:54 PM by Arno K.)
Post: #2
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RE: ∫−sin(x)*(cos(x))^7dx wrong answer?
The prime usually omits this constant as you can see when you enter a simple integral like int(x,x) which outputs 1/2*x^2, the 1/8 constant results from your trig->cos.
Arno |
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∫−sin(x)*(cos(x))^7dx wrong answer? [SOLVED] - vvolkan - 05-25-2018, 07:34 PM
RE: ∫−sin(x)*(cos(x))^7dx wrong answer? - Arno K - 05-25-2018 09:52 PM
RE: ∫−sin(x)*(cos(x))^7dx wrong answer? - vvolkan - 05-25-2018, 10:09 PM
RE: ∫−sin(x)*(cos(x))^7dx wrong answer? - Aries - 05-26-2018, 07:24 AM
RE: ∫−sin(x)*(cos(x))^7dx wrong answer? - Arno K - 05-26-2018, 05:40 AM
RE: ∫−sin(x)*(cos(x))^7dx wrong answer? - parisse - 05-26-2018, 05:58 AM
RE: ∫−sin(x)*(cos(x))^7dx wrong answer? - Arno K - 05-26-2018, 07:29 AM
RE: ∫−sin(x)*(cos(x))^7dx wrong answer? - Aries - 05-26-2018, 08:19 AM
RE: ∫−sin(x)*(cos(x))^7dx wrong answer? - parisse - 05-26-2018, 01:40 PM
RE: ∫−sin(x)*(cos(x))^7dx wrong answer? - vvolkan - 05-27-2018, 12:10 PM
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