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derivatives of a parametric equation
07-22-2018, 04:58 PM
Post: #3
RE: derivatives of a parametric equation
Code:

y1:=diff(y,t); x1:=diff(x,t); normal(diff(y1/x1,t)/x1);
Since x1=dx/dt and y1=dy/dt, dy/dx=y1/x1, then d2y/dx^2=d(dy/dx)/dx=d/dt(dy/dx)/x1
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derivatives of a parametric equation - DrD - 07-22-2018, 11:17 AM
RE: derivatives of a parametric equation - parisse - 07-22-2018 04:58 PM



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