HP-35: Sin and cos function formulas, another point of view
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08-15-2018, 01:46 AM
Post: #2
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RE: HP-35: Sin and cos function formulas, another point of view
I tried it on Mathematica. Both set of formulas about equally accurate.
My revised MAPM arbitrary precision C library go even furthur, doing 1/5 angle sin(5x) = sin(x) (16 sin(x)^4 - 20 sin(x)^2 + 5) cos(5x) = cos(x) (16 cos(x)^4 - 20 cos(x)^2 + 5) Both have the same polynomial form, so i define f(x), so that sin(5x) = f(sin(x)) cos(5x) = f(cos(x)) To speed up convergence, apply f() 4 times: sin(625x) = f(f(f(f(sin(x))))) cos(625x) = f(f(f(f(cos(x))))) |
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Messages In This Thread |
HP-35: Sin and cos function formulas, another point of view - sasa - 08-14-2018, 09:21 PM
RE: HP-35: Sin and cos function formulas, another point of view - Albert Chan - 08-15-2018 01:46 AM
RE: HP-35: Sin and cos function formulas, another point of view - Albert Chan - 08-15-2018, 03:57 AM
RE: HP-35: Sin and cos function formulas, another point of view - sasa - 08-16-2018, 08:46 AM
RE: HP-35: Sin and cos function formulas, another point of view - Thomas Klemm - 08-16-2018, 09:58 AM
RE: HP-35: Sin and cos function formulas, another point of view - Albert Chan - 08-16-2018, 03:26 PM
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