factor(x^4+1) and partfrac(1/(x^4+1))
10-23-2019, 11:45 AM
Post: #11
 rombva Junior Member Posts: 38 Joined: Oct 2019
RE: factor(x^4+1) and partfrac(1/(x^4+1))
(10-23-2019 08:36 AM)parisse Wrote:
(10-23-2019 04:05 AM)rombva Wrote:  How to find out the elements for algebraic extensions that provide factorization?

With solve.

factor(x^4+1,lvar(cSolve(x^4+1=0,x))) works fine.

For some polynomyals factor(f(x),lvar(cSolve(f(x)=0,x))) does nothing, for example, factor(x^7+2,lvar(cSolve(x^7+2=0,x))).

For some polynomyals factor(f(x),lvar(cSolve(f(x)=0,x))) doesn't return complete factorization, for example, factor(x^7+1,lvar(cSolve(x^7+1=0,x))).

For other polynomials the result contains a rootof([[][]]), for example, factor(x^5+2,lvar(cSolve(x^5+2=0,x))).

How to find out the elements for algebraic extensions that provide factorization? How to get factorization for these cases?
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 Messages In This Thread factor(x^4+1) and partfrac(1/(x^4+1)) - rombva - 10-21-2019, 02:05 PM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - goetz - 10-21-2019, 08:08 PM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - Tim Wessman - 10-22-2019, 01:48 AM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - rombva - 10-22-2019, 09:15 AM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - Joe Horn - 10-22-2019, 10:33 PM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - rombva - 10-23-2019, 04:10 AM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - Thomas_Sch - 10-23-2019, 12:08 PM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - Joe Horn - 10-23-2019, 09:04 PM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - parisse - 10-22-2019, 02:57 PM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - rombva - 10-23-2019, 04:05 AM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - parisse - 10-23-2019, 08:36 AM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - rombva - 10-23-2019 11:45 AM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - Aries - 10-22-2019, 07:11 PM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - lrdheat - 10-23-2019, 05:44 PM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - lrdheat - 10-23-2019, 05:46 PM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - Thomas_Sch - 10-23-2019, 06:03 PM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - parisse - 10-23-2019, 05:56 PM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - roadrunner - 10-23-2019, 06:03 PM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - Thomas_Sch - 10-23-2019, 06:07 PM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - roadrunner - 10-23-2019, 06:06 PM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - roadrunner - 10-23-2019, 07:15 PM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - Thomas_Sch - 10-23-2019, 08:15 PM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - rombva - 10-24-2019, 09:34 AM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - Tim Wessman - 10-24-2019, 09:59 AM

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