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[WP-34S] DEG and RAD - diffs
06-06-2014, 08:21 AM
Post: #20
RE: [WP-34S] DEG and RAD - diffs
\[\sinh(x) = \frac{(e^{x}-1)(e^{x}+1)}{2 e^{x}} = 2\cdot\frac{e^{\frac{x}{2}}-e^{-\frac{x}{2}}}{2}\cdot\frac{e^\frac{x}{2}+e^{-\frac{x}{2}}}{2} = 2\cdot\sinh(\frac{x}{2})\cdot\cosh(\frac{x}{2})\]

How do you avoid infinite recursion?
Or do you calculate \(e^x-1\) directly without extinction for small x?

Cheers
Thomas

PS: I should probably just have a look at the code.
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Messages In This Thread
[WP-34S] DEG and RAD - diffs - pito - 06-05-2014, 12:08 AM
RE: DEG and RAD - diffs - Paul Dale - 06-05-2014, 12:53 AM
RE: DEG and RAD - diffs - pito - 06-05-2014, 06:27 AM
RE: [WP-34S] DEG and RAD - diffs - pito - 06-05-2014, 01:38 PM
RE: [WP-34S] DEG and RAD - diffs - Dieter - 06-05-2014, 11:12 AM
RE: [WP-34S] DEG and RAD - diffs - pito - 06-05-2014, 06:04 PM
RE: [WP-34S] DEG and RAD - diffs - pito - 06-05-2014, 07:57 PM
RE: [WP-34S] DEG and RAD - diffs - pito - 06-05-2014, 10:07 PM
RE: [WP-34S] DEG and RAD - diffs - Thomas Klemm - 06-06-2014 08:21 AM
RE: [WP-34S] DEG and RAD - diffs - Dieter - 06-06-2014, 05:27 PM
RE: [WP-34S] DEG and RAD - diffs - pito - 06-07-2014, 12:57 PM



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