Eigenvector mystery

10202020, 12:08 AM
Post: #11




RE: Eigenvector mystery
(10192020 09:42 PM)Thomas Okken Wrote: Eigenvalues are values λ such that Av = λv, so you find them by solving Av − λv = 0, or equivalently, (A − λI)v = 0, where I is the identity matrix, or equivalently, A − λI = 0. That last form is also known as the characteristic equation of A, and, being a polynomial of the same degree as the dimension of A, you can find its solutions, and thus the eigenvalues of A, using a polynomial root finder. Thomas is fully right. You can find a program to compute the coefficients of the Characteristic Polynomial (its roots are the eigenvalues) for real or complex matrices in my article: HP Article VA047  Boldly Going  Eigenvalues and Friends Also, there are many solved examples in the article, to make the matter crystalclear. V. All My Articles & other Materials here: Valentin Albillo's HP Collection 

« Next Oldest  Next Newest »

User(s) browsing this thread: 1 Guest(s)