Prime calculator sum(1.0002^n/n, 1, 20000)

[Gil]

How to calculate
sum(1.0002^n/n, 1, 20000)
with the build-in template sigma?

To get an approximate answer,
I have to calculate
sum(1.0002^n/n, 1, 10000) + sum(1.0002^n/n, 10001,20000) = 10.9246.

Somewhat cumbersome.

On the HP50G, I get the wished answer by writing
directly sum(1.0002^n/n, 1, 20000).

Thanks for your help.

Regards,
Gil