Free42 and cube root of complex number
02-24-2021, 10:26 AM
Post: #6
 Albert Chan Senior Member Posts: 1,842 Joined: Jul 2018
RE: Free42 and cube root of complex number
(02-24-2021 02:02 AM)Thomas Okken Wrote:  atan2(-0, -8) => -pi, while atan2(0, -8) => pi

-pi < arg(z) ≤ pi

Since polar form and rectangular form should match, I think -8 ± 0i should be adjusted to -8 + 0i = 8 exp(i*pi)

For the same reason, sqrt(-4 - 0i) = sqrt(-4 + 0i) = 2i

4 [ENTER] 0 [COMPLEX] [+/-] [SQRT] ﻿ ﻿ ﻿ ﻿ ﻿ ﻿ → 2i
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 Messages In This Thread Free42 and cube root of complex number - Ajaja - 02-23-2021, 11:05 PM RE: Free42 and cube root of complex number - Thomas Okken - 02-24-2021, 02:02 AM RE: Free42 and cube root of complex number - Albert Chan - 02-24-2021 10:26 AM RE: Free42 and cube root of complex number - Paul Dale - 02-24-2021, 02:52 AM RE: Free42 and cube root of complex number - J-F Garnier - 02-24-2021, 08:28 AM RE: Free42 and cube root of complex number - Werner - 02-24-2021, 08:59 AM RE: Free42 and cube root of complex number - Thomas Okken - 02-24-2021, 01:35 PM RE: Free42 and cube root of complex number - Albert Chan - 02-24-2021, 02:47 PM RE: Free42 and cube root of complex number - Thomas Okken - 02-24-2021, 02:53 PM RE: Free42 and cube root of complex number - Werner - 02-25-2021, 06:08 AM RE: Free42 and cube root of complex number - Albert Chan - 02-25-2021, 04:40 PM

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